y-4=-1/2(x-8)^2

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Solution for y-4=-1/2(x-8)^2 equation: 


x in (-oo:+oo)

y-4 = (-1/2)*(x-8)^2 // - (-1/2)*(x-8)^2

y-((-1/2)*(x-8)^2)-4 = 0

(1/2)*(x-8)^2+y-4 = 0

1/2*(x-8)^2+y-4 = 0

1/2*(x-8)^2+y-4 = 0

1/2*x^2-8*x+y-4+32 = 0

1/2*x^2-8*x+y+28 = 0

1/2*x^2-8*x+y+28 = 0

1/2*x^2-8*x+y+28 = 0

DELTA = (-8)^2-(1/2*4*(y+28))

DELTA = 64-2*(y+28)

64-2*(y+28) = 0

64-2*(y+28) = 0

8-2*y = 0

8-2*y = 0

8-2*y = 0 // - 8

-2*y = -8 // : -2

y = -8/(-2)

y = 4

DELTA = 0  <=>  t_3 = 4

x = 8/(1/2*2) i y = 4

x = 8 i y = 4

( x = ((64-2*(y+28))^(1/2)+8)/(1/2*2) or x = (8-(64-2*(y+28))^(1/2))/(1/2*2) ) i y > 4

( x = (64-2*(y+28))^(1/2)+8 or x = 8-(64-2*(y+28))^(1/2) ) i y > 4

y-4 > 0

y-4 > 0 // + 4

y > 4

x in { 8, (64-2*(y+28))^(1/2)+8, 8-(64-2*(y+28))^(1/2) }

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